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frosja888 [35]
3 years ago
5

Decrease £16855.21 by 13.5% Give your answer rounded to 2 DP.

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

Answer:

<h2>£ 14,579.75</h2><h2 />

Step-by-step explanation:

= £16855.21  -  ( £16855.21 x <u>13.5% )</u>

                                                 100

= £ 14,579.75

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List the perfect squares that are between 25 and 100.
Aleks04 [339]

Perfect squares are rational numbers multiplied by themselves. Here are the perfect squares between 25 and 100:

5*5=25

6*6=36

7*7=49

8*8=64

9*9=81

10*10=100

Hope this helps :)

7 0
3 years ago
Read 2 more answers
PLEASE ANSWER FAST!!!
NemiM [27]

Answer:

A- 3,000 = 50(60) + b

B- 2,100 = 50(42) + b

Step-by-step explanation:

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4 0
4 years ago
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James used a substitution to solve this system of equations. Which equation could be a result of his first step? 2x+3y=12 y=x+1.
Blizzard [7]

Answer:

x = 1.5

y = 3

Step-by-step explanation:

to solve this system of equation using the substitution methods we say let

2x+3y=12................................... equation 1

y=x+1.5..................................... equation 2

substitute equation 2  into equation 1

2x+3y=12................................... equation 1

2x + 3( x + 1.5) = 12

2x + 3x + 4.5 = 12

5x + 4.5 = 12

collect the like terms

5x = 12 - 4.5

5x = 7.5

divide both sides by the coefficient of x which is 5

5x/5 = 7.5/5

x = 1.5

put x = 1.5 into equation 2

y=x+1.5..................................... equation 2

y = 1.5 + 1.5

y = 3

therefore the value of x = 1.5 and y = 3 respectively.

5 0
3 years ago
6
IgorC [24]

Answer:

12 less than or equal to 2

Step-by-step explanation:

7 0
3 years ago
Prove the statement holds for all positive integers:<br><br> 2 + 4 + 6 + ... + 2n = n² + n
crimeas [40]

Proving a relation for all natural numbers involves proving it for n = 1 and showing that it holds for n + 1 if it is assumed that it is true for any n.

The relation 2+4+6+...+2n = n^2+n has to be proved.

If n = 1, the right hand side is equal to 2*1 = 2 and the left hand side is equal to 1^1 + 1 = 1 + 1 = 2

Assume that the relation holds for any value of n.

2 + 4 + 6 + ... + 2n + 2(n+1) = n^2 + n + 2(n + 1)

= n^2 + n + 2n + 2

= n^2 + 2n + 1 + n + 1

= (n + 1)^2 + (n + 1)

This shows that the given relation is true for n = 1 and if it is assumed to be true for n it is also true for n + 1.

<span>By mathematical induction the relation is true for any value of n.</span>

6 0
3 years ago
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