How far away from zero on the x-axis is the point (4,7)
2 answers:
Zero on the x-axis is the origin, (0,0) so the distance from the origin to (4,7) is going to be, according the the Pythagorean Theorem...
d^2=x^2+y^2
d^2=4^2+7^2
d^2=16+49
d^2=65
d=√65 since √65=√(5*13) and 5 and 13 are both prime this cannot be simplified any further...
So the distance is just √65 units. (approximately ≈8.06 units)
It is 4 units or 11 units apart
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<h2>
Answer:</h2>
x is -5 ; y is 6
<h2>
Step-by-step explanation:</h2>
x=-47+7y
-6x-8y=-18
-6(-47+7y)-8y=18
y=6
x=-47+7*6
x=-5
Step-by-step explanation:
log_6^36+log_6^216
= log_6^ (36 × 216)
= log_6^ (6² × 6³)
= log_6^ (6^5)
= 5
x = 2
Step-by-step explanation:
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5 m by 10 m
5+5=10 and 10+10=20
10+20=30 which is the full perimeter