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yKpoI14uk [10]
3 years ago
6

Tyson has a collection of 60 sports ribbons. Of these ribbons, 30% are first place ribbons, 45% are second place ribbons, and th

e rest are third place ribbons. How many third place ribbons are in Tyson’s sports ribbon collection?
15
27
32
18
give me a serious answer or I will report you and your account will be deleted
Mathematics
1 answer:
sesenic [268]3 years ago
4 0
The answer is 15.

30% of 60 = 18
45% of 60 = 27
27 + 18 = 45
60 - 45 = 15
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Tyler went to the grocery store and purchased cans of soup and frozen dinners. Each can of soup has 300 mg of sodium and each fr
Katena32 [7]

Answer:

<u>Tyler purchased 10 cans of soup and 5 frozen dinners.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Amount of sodium per can of soup = 300 mg

Amount of sodium per frozen dinner = 550 mg

They all collectively contain 5,750 mg of sodium

Tyler purchased twice as many cans of soup as frozen dinners

2. Determine the number of cans of soup purchased and the number of frozen dinners purchased.

Let s to represent the number of cans of soup Tyler purchased

Let d to represent the number of frozen dinners Tyler purchased

Let's write our equation of systems:

s = 2d (1st equation)

300s + 550d = 5,750 (2nd equation)

************************************************

Substituting s and solving for d in the 2nd equation:

300s + 550d = 5,750

300 * 2d + 550d = 5,750

600d + 550d = 5,750

1,150d = 5,750

d = 5,750/1,150

<u>d = 5 ⇒ s = 2 * 5 = 10</u>

<u>Tyler purchased 10 cans of soup and 5 frozen dinners.</u>

Let's prove d = 5 and s = 10 are correct:

300 * 10 + 550 * 5 = 5,750

3,000 + 2,750 = 5,750

5,750 = 5,750

<u>We proved d = 5 and s = 10 are correct</u>

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3 years ago
BRAINLIEST! URGENT HELP!!!!!!
Vikki [24]
It's -5/2,-4 is right. ok?
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3 years ago
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A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%
Mamont248 [21]

Answer:

a. A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\

b. \frac{dA}{dt}= -11.25 \frac{mg}{h}

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

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likoan [24]
The answer to this question is b
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Answer: x= 2

Step-by-step explanation:

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