Answer: 7 rides
Step-by-step explanation:
Since it takes $4 to enter the fair, you have
$21.50 - $4 = $17.50 left to spend on rides
$17.50/$2.50 = 7 rides
hope this helps!
Might have to experiment a bit to choose the right answer.
In A, the first term is 456 and the common difference is 10. Each time we have a new term, the next one is the same except that 10 is added.
Suppose n were 1000. Then we'd have 456 + (1000)(10) = 10456
In B, the first term is 5 and the common ratio is 3. From 5 we get 15 by mult. 5 by 3. Similarly, from 135 we get 405 by mult. 135 by 3. This is a geom. series with first term 5 and common ratio 3. a_n = a_0*(3)^(n-1).
So if n were to reach 1000, the 1000th term would be 5*3^999, which is a very large number, certainly more than the 10456 you'd reach in A, above.
Can you now examine C and D in the same manner, and then choose the greatest final value? Safe to continue using n = 1000.
Original price is $150 so you times 150 by 0.40
150 x 0.40 = 60
So you take the $150 and you subtract $60 from $150
150 - 60 = 90
So the answer is $90
Answer:
I only have the first two, sorry...
Step-by-step explanation:
Yes; 2/3
