Hello! So Angie reads 60 pages in 2 hours, without the TV on. 60/2 is 30. She reads 30 pages an hour without the TV on, and 24 pages with the TV off. To find the percent of her reading rate with the TV on instead of off, we can just divide both of the reading rates. 24/30 is 0.8. Multiply that by 100 and you get 80% in percent form. There. Angie's reading rate with the TV on is 80% of her reading rate with the TV off. The answer is B: 80%.
Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles. 5/6 of an hour times 36 mph = 30 miles.mph looks good. going he was with the wind. his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14. combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good. answer is W = 7 and A = 43.