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irinina [24]
2 years ago
12

Please help (links will lead to a report)

Mathematics
1 answer:
mestny [16]2 years ago
6 0

Answer:

the shaded part is 60% of the thing

Step-by-step explanation:

3/5 = 60%

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Answer: -2/3x+/2/5

Step-by-step explanation:

−2(13x−15)=  (−2) (13x  + −15) =   (−2)(13x)+(−2)(−15)

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A student finished 8 of her homework problems in class. If the ratio of problems she finished to problems she still had left was
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Tickets for an American Baseball League game for 3 adults and 3 children cost less than $75, while tickets for 2 adults and 4 ch
nikitadnepr [17]
<h3>No, the cost of 1 adult ticket cannot be $ 20 and the cost of 1 children ticket is not $ 8.</h3>

Step-by-step explanation:

Let us assume the cots of ticket for 1 adult  = $ x

Let us assume the cots of ticket for 1 children  = $ y

So, the cost of ticket for 3 adults = 3 x ( Cost of 1 adult ticket) =  3 x

The cost of ticket for 3 children  = 3 x ( Cost of 1 children ticket)  =  3 y

Also, given the combined cost of 3 adult and children ticket is less than $75.

⇒  3 x +  3  y < 75  ... (1)

Similarly,  the cost of ticket for 2 adults = 2 x

The cost of ticket for 4 children   = 4 y

⇒  2 x +  4  y < 62  ... (2)

Now, solving for the values of x and y, we get:

3 x + 3 y < 75 or, x + y < 25   ⇒ x = 25 - y ( substitute in 2)

2 x +  4  y < 62  or, x +  2 y < 31

⇒   25  - y + 2 y < 31

or, y + 25 < 31

or, y < 6

⇒ x = 25 - 6  = 19

or, x < 19

So, the cost of 1 adult ticket  is x and is less than $19.

The cost of 1 child ticket  is y  and is less than $6.

Hence, by above statement, NO the cost of 1 adult ticket  can not be $ 20 and the cost of 1 children ticket is not $ 8.

4 0
3 years ago
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