Describe a real world problem you can solve with the help of a yard stick

1 answer:

3 0

Fiona has a patch of backyard behind her house in a meadow (she lives in the country). Seeing as the soup kitchen miles down the road is having some issues with the lack of vegetables to cook food for the poor, she decides to make the small rectangular patch of fertile soil into her own veggie garden.
Fiona wants to measure the perimeter of her patch using a few rulers, but she only has yard sticks. Without any rulers to measure with, Fiona decides to use the yard sticks anyway, and begins to measure the plot of land.
The length of the patch is 59 yard sticks long. The width is 24 yard sticks long. Using the concept of 1 yard = 3 feet, find out how many feet are in the garden's perimeter. Write your answer down in words and another in a picture.

I hope you like this problem, and that you didn't rage over my long period of time typing this! Have a good night! :P

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Find the surface area of the prism A. 90 cm^2 B. 96 cm^2 C. 150 cm^2 D. 156 cm^2

creativ13 [48]

Answer:

D. 156 cm²

Step-by-step explanation:

The full surface area is:

S = Ph + 2B = (3 + 4 + 5)*12 + 2(1/2*3*4) = 144 + 12 = 156 cm²

Correct choice is D

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2 years ago

Read 2 more answers

Can anyone help me solve these please

pickupchik [31]

R^2+(ab)^2= (ao)^2
ab=6
ao=11.7

Plug in

r^2+6^2=11.7^2

simplify

r^2+36= 136.89
-36 both sides

r^2=100.89
square root both sides

r= 10.04 rounded 10

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3 years ago

What is the y-intercept of this function? f(x) = 2(x - 7)2 – 32

LUCKY_DIMON [66]

We are given the following function and want to find the y-intercept:

$f(x)=2(x-7)^2-32$

Just substitute the value x=0 into the equation to find the value of the y-intercept:

$y=2(0-7)^2-32$

Simplify

$=2(49)-32$

Simplify again

$=66$

Since the value of f(x), or y, when x=0 is 66, the y-intercept of this function is 66.

Let me know if you need any clarifications, thanks!

~ Padoru

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3 years ago

Evaluate the summation of negative 2 n minus 3, from n equals 2 to 10..

Alisiya [41]

$\bf \sum\limits_{n=2}^{10}~-2n-3$

so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".

however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus k = n - 1.

however, if k = n - 1, then k + 1 = n. So let's use those fellows then,

$\bf \sum\limits_{n=2}^{10}~-2n-3\qquad 
\begin{cases}
k=n-1\\
k+1=n
\end{cases}\implies \sum\limits_{k=1}^{9}~-2\stackrel{n}{(k+1)}-3
\\\\\\
\sum\limits_{k=1}^{9}~-2k-2-3\implies \sum\limits_{k=1}^{9}~-2k-5\implies \sum\limits_{k=1}^{9}~-2k-\sum\limits_{k=1}^{9}~5
\\\\\\
-2\sum\limits_{k=1}^{9}~k-\sum\limits_{k=1}^{9}~5\implies -2\left( \cfrac{9(9+1)}{2} \right)\qquad -\qquad (9\cdot 5)
\\\\\\
-2(45)-45\implies -90-45\implies -135$

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2 years ago

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krok68 [10]

Answer:

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