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4 years ago

4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?

1 answer:

4 0

Distance between T(80, 20) and U(20, 60) = sqrt((20 - 80)^2 + (60 - 20)^2) = sqrt((-60)^2 + (40)^2) = sqrt(3600 + 1600) = sqrt(5200) = 72.11 units

Distance between T(80, 20) and V(110, 85) = sqrt((110 - 80)^2 + (85 - 20)^2) = sqrt((30)^2 + (65)^2) = sqrt(900 + 4225) = sqrt(5125) = 71.59

Distance between U(20, 60) and V(110, 85) = sqrt((110 - 20)^2 + (85 - 60)^2) = sqrt((90)^2 + (25)^2) = sqrt(8100 + 625) = sqrt(8725) = 93.41

Therefore, shortest distance for the trip = 71.59 + 93.41 = 165 units.

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A group of tourists can be sorted into tour boats in groups of 4 or in groups of 6. In either case, there are no empty seats. Fi

Jobisdone [24]

Answer: there are 36 tourists.

Step-by-step explanation:

Ok, we have two integer numbers:

T, the number of tourists and S, the number of seats.

Such that, if we divide the tourists into groups of 4 and in groups of 6, we end with no empty seats.

Knowing that the number S must be an integer, and when we divide T into groups of 4 and 6 we end with no empty seats, this means that T can be divided by 4 and by 6.

This means that T is a common multiple of 4 and 6

Now, we also know that 25 < T < 45.

Then let's see which ones are the multiples of 4 between 25 and 45.

4*7 = 28

4*8 = 32

4*9 = 36

4*10 = 40

4*11 = 44.

Now, the multiples of 6 in that range are:

6*5 = 30

6*6 = 36

6*7 = 42.

You can see that 36 is a common multiple, other way to see it is:

4*9 = (2*2)*(3*3) = 2*2*3*3 = (2*3)*(2*3) = 6*6

So the numer of tourist must be 36.

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3 years ago

Please help me with this question is hard and i will give you a Brainiest

Westkost [7]

Answer:

Step-by-step explanation:

10(x-2)=-20

10x-20=-20

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3 years ago

The fee to rent a hall for a wedding is $1450 plus $50 per hour. For how many hours can it be rented forband stay within a budge

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2,100-1,450= 650
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3 years ago

In a histogram, the proportion of the total area which must be to the left of the median is:

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Answer:

A. exactly 0.50

Step-by-step explanation:

We have been given a statement. We are asked to choose the correct option about given statement.

We know that every histogram has 5 points summary.

1st point is known as minimum point, 2nd point is first quartile, 3rd point is median, 4th point is upper quartile and 5th point is maximum point.

In a normal distribution 25% of the data points are to the left 1st quartile, 50% of the data points are to the left of median and 75% of the data points are to the left 2nd quartile.

$50\%=\frac{50}{100}=0.50$

Therefore, exactly 0.50 of the total area which must be to the left of the median.

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3 years ago

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Answer:

Please find attached the required drawing that illustrates the given situation

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With a driving speed of 0.003 miles per second, which is approximately 4.83 meters per second, we have the drawing of the graph that represent the given situation which is create with Microsoft Excel and attached alongside here

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