4. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85). What is the shortest possible distance for the trip?
1 answer:
Distance between T(80, 20) and U(20, 60) = sqrt((20 - 80)^2 + (60 - 20)^2) = sqrt((-60)^2 + (40)^2) = sqrt(3600 + 1600) = sqrt(5200) = 72.11 units
Distance between T(80, 20) and V(110, 85) = sqrt((110 - 80)^2 + (85 - 20)^2) = sqrt((30)^2 + (65)^2) = sqrt(900 + 4225) = sqrt(5125) = 71.59
Distance between U(20, 60) and V(110, 85) = sqrt((110 - 20)^2 + (85 - 60)^2) = sqrt((90)^2 + (25)^2) = sqrt(8100 + 625) = sqrt(8725) = 93.41
Therefore, shortest distance for the trip = 71.59 + 93.41 = 165 units.
You might be interested in
Answer:the answer is d
Step-by-step explanation:
Answer:
4 , 2, 8, 4 ..............
463 is the answer because-3 m + 4 would equal 463
Hey there! I'm happy to help!
If you raise a fraction to an exponent, you apply that exponent to the numerator and the denominator. This would give us
.
Have a wonderful day! :D
ABC = 180 degrees because a triangle is always equal to 180degree