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hram777 [196]
4 years ago
11

If 3^-x=2 what does 3^2x equal?

Mathematics
2 answers:
RSB [31]4 years ago
8 0
I think 1/4 most likely
marissa [1.9K]4 years ago
7 0

Answer:

nice question...

so here we go

3^ -x = 1 / 3^x

so 1/ 3^x = 2 so 3^x = 1/2

we can write 3^2x as 3^x multiplied by 3^x right?..(law of exponents)

recall that 3^x =1/2

so now according to question we have to find the value of 3^2x =  1/2 * 1/2 = 1/4

Step-by-step explanation:

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Answer:

d = 5

Step-by-step explanation:

d = \sqrt{(5 - 2)^{2} + (5-1)^{2}  }

d = \sqrt{(3)^{2} + (4)^{2}  }

d = \sqrt{(9) + (16)}

d = \sqrt{25}

d = 5

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3 years ago
Quadrilateral RPQS is a rectangle. Label the missing measures. HELP PLEASEEEEEEEE
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Step-by-step explanation:

7.5

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Reflect the given triangle over<br> the line y=x.<br><br> [3 6 3<br> -3 3 3]
iragen [17]

If reflected over y = x

<u>then use</u>

<u />\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]

=====================

\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]  \left[\begin{array}{ccc}3&6&3\\-3&3&3\end{array}\right]

similar as (x, y) → (y, x)

<u>multiply the matrixes to get the final answer</u>

\left[\begin{array}{ccc}(3*0+1*-3)&(6*0+1*3)&(3*0+1*3)\\(3*1+(-3*0)&(1*6+0*3)&(1*3+0*3)\end{array}\right]

\left[\begin{array}{ccc}-3&3&3\\3&6&3\end{array}\right]

3 0
2 years ago
Cube A has a volume of 125 cubic inches. The edge lengths of cube B measure 4.8 inches. Which cube is larger and why?
Anestetic [448]

Answer: Cube A is larger. This is because volume is found by multiplying length × width × height. The length, width, and height of a cube are ALWAYS equal. Therefore if cube B has a length of 4.8 inches it also has a height of 4.8 inches and a width of 4.8 inches. To find its volume multiply 4.8×4.8×4.8 this will give you 110.592 cubic inches. This means cube A is larger.


4 0
4 years ago
Solving each system by Eliminating <br> x-y-2z=4<br> -x+2y+z=1<br> -x+y-3z=11
elena-s [515]

Answer:

<em>x = 0 </em>

<em>y = 2</em>

<em>z = -3</em>

Step-by-step explanation:

x-y-2z=4     (1)

-x+2y+z=1   (2)

-x+y-3z=11  (3)

(1) + (3) = x-y-2z + (-x)+y-3z   = 4+11

           = -5z                          = 15

-> z = -3

(1) + (2) = x - y - 2z + (-x) + 2y + z = 4+1

           = y-z                                 = 5

           = y- (-3)                             = 5

-> y = 2

(1) = x-y-2z            = 4  

   = x - 2 - 2 * (-3) = 4

-> x = 0

3 0
3 years ago
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