1.
<span>(x-4)^2 -28 = 8
</span>(x-4)^2 = 8 + 28 = 36
<span>(x-4) = +/-6
x = 6 + 4 or -6 + 4
x = 10 or -2
2.
Mistake in </span><span>Step 5: x – 3 = 16
</span><span>Step 4: (x – 3)² = 16
</span><span>Step 5: (x – 3) = +/-4
Step 6: x = 4 + 3 or -4 + 3
Step 7: x = 7 or -1
3.
</span><span>x^2 - 4x + 3 = 0
</span><span>quadratic eqn x = [-b +/- sqrt(b^2-4ac)]/2a
where in this case
a = 1, b = -4, c = 3
x = </span> [-(-4) +/- sqrt((-4)^2-4*1*3)]/2*1
= [4 +/- sqrt(16 - 12)]/2
<span>= [4 +/- sqrt(4)]/2
= [4 +/- 2]/2
= 6/2 or 2/2
= 3 or 1
</span>
3 √x. Times 8√x^5. That’s the answer idk really how to explain it
Answer: 15
Step-by-step explanation:
max - min 15-0 = 15
Where it the rest of the question????
Answer:
12x^3 -28x^2 -21x +30
Step-by-step explanation:
1) Distribute!
(6x-5)(2x^2-3x-6) = 12x^3 -18x^2 - 36x -10x^2 +15x+30
2) Combine like terms!
12x^3 -18x^2 - 36x -10x^2 +15x+30 = 12x^3 -28x^2 -21x +30
Answer is:
12x^3 -28x^2 -21x +30
Hope it helps!!
