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2 years ago

AP statistics HELP PLEASE!!!!

Mathematics

1 answer:

Novay_Z [31]2 years ago

3 0

The data consists of 25 observations - this is just how many people were involved in the study. (count the rows, excluding the header)

As for number of variables, that depends on the aim of the study. More likely than not, I suspect the name of each person involved is irrelevant, which leaves 7 variables. (count the columns, excluding the first)

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X-6y=11 pls solve for y in a fraction or decimal

gulaghasi [49]

There is no y so I wouldn’t be able to answer

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2 years ago

Mrs. Palmer asks her students to find the area of the tops of their desks.

xxTIMURxx [149]

Answer:

12 square feet

Step-by-step explanation:

The shape of the top of the desk is a trapezoid.

A = (b1 + b2)h/2

A = (5 ft + 3 ft)(3 ft)/2

A = (8 ft)(3 ft)/2

A = 24 ft^2/2

A = 12 ft^2

Answer: 12 square feet

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2 years ago

Marcia biked 600 meters on friday. On saturday, she biked 3 kilometers. One sunday she biked 2 kilometers and 700 meters. How ma

zepelin [54]

Answer:

6.3 km.

Step-by-step explanation:

The question asks for kilometers, so all amounts have to be calculated in the same units -- kilometers.

Convert meters to kilometers.

600 m = .6 km

700 m = .7 km.

Add the amounts:

Fri.: .6 km

Sat. 3 km

Sun.: 2.7 km.

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6.3 km.

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2 years ago

A car can travel 393.3 miles on 28.1 gallons of gas. How far can it travel on 16.7 gallons?

grigory [225]

In the early months of some year one site added 0.4 million new accounts every day, At this rate , how many days would be needed to add 24 million new accounts?

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2 years ago

The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma

andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

$\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end$

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

$\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end$

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

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3 0

1 year ago