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Alecsey [184]
2 years ago
14

Evaluate log1∕6 36. please help

Mathematics
1 answer:
Sholpan [36]2 years ago
4 0

\log_{\tfrac 16}   36 \\\\\\=\dfrac{\ln 36}{ \ln \left(\tfrac 16\right)}\\\\\\=\dfrac{ \ln 6^2}{\ln (6^{-1})}\\\\\\=\dfrac{2 \ln 6}{-1 \ln 6}\\\\= - 2

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