Answer:
Average atomic mass = 21.38 amu.
Explanation:
Given data:
Mass of first isotope = 21 amu
Abundance of first isotope = 62%
Mass of second isotope = 22 amu
Abundance of second isotope = 38%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (62×21)+(38×22) /100
Average atomic mass = 1302 +836 / 100
Average atomic mass = 2138 / 100
Average atomic mass = 21.38 amu.
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Answer:
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Explanation:
1. A restriction enzyme, restriction endonuclease, an enzyme that cleaves DNA into small fragments at or near specific recognition sites (different restriction enzyme has different restriction site) within molecules known as restriction sites.
2. Restriction enzymes are found in archaea and bacteria.
3 And in bacteria and archaea they provide a defence mechanism against invading viruses.
4. Each restriction enzyme cut at the specific site, because each restriction enzyme have specific recognition site.
Jack. A signpost is a non-living thing and non living things do not grow. Sam is an adult and he has stopped growing already. Jack is a child and will continue growing the next few years.