The point (2, 5) is represented on the graph. Which point also belongs on this graph?
2 answers:
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Answer:
A: -4
B: 4
C: m(x)<h(x) for every x, t.e m(x)>h(x) cann’t be treu for any value of x.
Step-by-step explanation:
I’m not sure what is fubction m. I will suppose it is linear function.
For example m(x)=x/2-2.
Part A: h(4)-m(16)=1/2(4-2)^2 - 16/2-2=2-6=-4
Part B: y-intersection on h(x), we find how is h(0). So h(0)=1/2(0-2)^2=2.
For m(x), m(0)=0/2-2=-2. So their y-intersections are fare away 4. (See photo)
Part C: First we chak if there any intersection between h and m.
1/2(x-2)^2=x/2-2, si we have
x^2-4x+4-x+4=0
X^2-5x+8=0,
D=5^2-4*8=25-32<0, so m and h don’t have intersection, and from graph we can see that for every value of x, m(x) will always be less than h(x).
Photo: blue is h(x), green is m(x)
1. horizontal shrink by factor of 2/3 means multiply outside the f(x) or outside the x^2 by 2/3:
(2/3)•f(x)
2. translation left 5 units means "x+5" inside:
(2/3) • f(x+5)
3. tranlate down 2 units means "-2" outside:
(2/3) • f(x+5) -2
or (2/3) (x+5)^2 - 2
or
You use the definition of median and interquartile range. The def. of a median is the number in the middle of the data set, so the number 6 would be in the middle. Making a box and whisker plot(shown below) with the data set separates the data set into 4 "quartiles" or parts. The interquartile range is the last line in the box(Q3) minus the first line in the box(Q1). So something minus somthing must equal 5.
Data set: 1,2,3,6,8,8,10
It doesn't matter what the other numbers are as long as the median is 6 and the interquartiel range is 6.
Data set: 1,2,3,6,8,8,10
It doesn't matter what the other numbers are as long as the median is 6 and the interquartiel range is 6.
Answer:
Step-by-step explanation:
Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:
Next we factor what we can so we can further simplify the rest of the equation:
We can now cancel out (x+2)
Next we factor out even more:
We cancel out x-4 and reduce the 3 and 6 into simpler terms:
And we can now simplify it to: