Answer: x = - 12/9 ( the equation is negative)
Step-by-step explanation:
\frac{5}{3}x+\frac{1}{3}=13+\frac{1}{3}x+\frac{8}{3}x
\frac{5}{3}x=3x+\frac{38}{3}
\frac{5}{3}x-3x=3x+\frac{38}{3}-3x
-\frac{4}{3}x=\frac{38}{3}
3\left(-\frac{4}{3}x\right)=\frac{38\cdot \:3}{3}
-4x=38
\frac{-4x}{-4}=\frac{38}{-4}
x=-\frac{19}{2}
The solution to the system is (90,40)....x = adults and y = child's...so x = 90 (there were 90 adult tickers) and y = 40 (there were 40 child tickets)...u already had the answer right in front of you
Answer:
The probability of getting two of the same color is 61/121 or about 50.41%.
Step-by-step explanation:
The bag is filled with five blue marbles and six red marbles.
And we want to find the probability of getting two of the same color.
If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.
In other words, we can find the independent probability of each case and add the probabilities together*.
The probability of getting a red marble first is:
Since the marble is replaced, the probability of getting another red is: 
The probability of getting a blue marble first is:
And the probability of getting another blue is:
So, the probability of getting two of the same color is:
*Note:
We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.
Answer: function 1
Rate of change of function 1:
Following the format of y=mx+c, the rate of change should be m, so, the rate of change for function 1 = 4
To find the gradient (rate of change):
The two points the line passes through are (x1, y1) and (x2, y2), which in this case is (1, 6) and (3, 10)
(Doesn't matter which is which but you need to make sure that once you decide which is which, you stick to it)
To calculate the gradient, you substitute these values following (y1 - y2)/(x1 - x2)
Gradient of function 2 = (10 - 6)/(3 - 1)
= 2
Therefore, since 4 > 2, rate of change of function 1 > rate of change of function 2.
