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Brums [2.3K]
3 years ago
8

Please help me im so confused i cant fail

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0

Step-by-step explanation:

since the volume formula is given in the picture,

volume of the cylinder = π x 3.75^2 x 6.21 = 274.349....in^3 (this is the exact answer)

HOWEVER,

since question says round off to nearest whole number,

Volume = 3 x 4^2 x 6 = 288in^3

therefore, answer = option C.

Hope that helps.

If you like to venture further, do check out my insta <em>(learntionary)</em> where I constantly post math tips! Thanks!

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marissa [1.9K]
The answer is 7/8!!!!!!
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3 years ago
WILL GIVE BRAINLIEST TO BEST ANSWER! HELP ASAP!
Aleks [24]

Answer:

120 ft

Step-by-step explanation:

The distance the gravel covers is the total distance times the percentage that the gravel covers

We know the gravel covers 66 ft and the percentage is 55%

distance gravel = total distance * percentage

66 = total distance * 55%

66 = total distance *.55

Divide each side by .55

66/.55 = total distance *.55/.55

120 = total distance

8 0
3 years ago
Which best describes the error in finding the simple interest earned on $500 at 6% for 18 months?
valentinak56 [21]
$540.00 is the interest
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7 0
3 years ago
Fh
scZoUnD [109]

Answer:

ok so just get the v12{{9-))0} and =14

Step-by-step explanation:

4 0
2 years ago
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
3 years ago
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