<h2>Length = 11</h2><h2>Width = 6</h2>
The area of a rectangle is 66 ft^2:
L * W = 66
Length of the rectangle is 7 feet less than three times the width:
L = 3W-7
Substitute L in terms of W:
(3W-7) * W = 66
Factorise the equation:
3W^2 -7W = 66
3W^2 - 7W - 66 = 0
Factors of 66 =
1 66, 2 33, 3 22, 6 11
(3W + 11) (W - 6) = 0
Solve for W:
3W + 11 = 0
3W = 11
W = 3/11
W - 6 = 0
W = 0 + 6
W = 6
Using the original equation, find L:
L = 3W-7
L = 3(6)-7
L = 18-7
L = 11
L * W = 66
11 * 6 = 66
use one five dollar box then use 4 4 $ boxes then its five dollar boxes the rest of the way so it would be 59 5$ boxes then Four 4$ boxes
Answer:
(x - 7)² + (y + 2)² = (2√13)²
Step-by-step explanation:
We already know that the center is at (7, -2), but must find the radius. The radius is the distance between the points (7, -2) and (1, -6):
r = √ [6² + 4²] ) = √(36 + 16) = √52 = √4√13 = 2√13.
Then the desired equation is (x - 7)² + (y + 2)² = (2√13)²
