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emmainna [20.7K]
2 years ago
7

What is the constant rate change shown in the graph below?​

Mathematics
2 answers:
Montano1993 [528]2 years ago
6 0

Answer:

the two points be

(0,0) and (1,-3)

slope [m]=[-3-0]/[1-0]=-3

constant rate is-3.

ohaa [14]2 years ago
3 0
The constant rate of change is 5 because
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A rope tied from a tent pole to a take in the ground forms 55 degrees angle with the ground. The pole is 3 feet from the stake,
grin007 [14]

Given:

A rope tied from a tent pole to a stake in the ground forms 55 degrees angle with the ground.

The pole is 3 feet from the stake.

To find:

The length of the rope to the nearest tenth of a foot.

Solution:

First draw a diagram according to the given information as shown below.

We know that, in a right angled triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

In triangle ABC,

\cos 55^\circ=\dfrac{BC}{AC}

0.573576=\dfrac{3}{AC}

AC=\dfrac{3}{0.573576}

AC=5.23034

AC\approx 5.2

Therefore, the length of the rope is 5.2 foot.

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Which expression is a fourth root of -1+isqrt3?
aleksklad [387]

Answer:

Step-by-step explanation:

\sf n^{th} roots of a complex number is given by DeMoivre's formula.

   \sf \boxed{\bf r^{\frac{1}{n}}\left[Cos \dfrac{\theta + 2\pi k}{n}+i \ Sin \ \dfrac{\theta+2\pi k}{n}\right]}

Here, k lies between 0 and (n -1) ; n is the exponent.

\sf -1 + i\sqrt{3}

a = -1 and b = √3

\sf \boxed{r=\sqrt{a^2+b^2}} \ and \ \boxed{\theta = Tan^{-1} \ \dfrac{b}{a}}

\sf r = \sqrt{(-1)^2 + 3^2}\\\\ = \sqrt{1+9}\\\\=\sqrt{10}

                   \sf \theta = tan^{-1} \ \dfrac{\sqrt{3}}{-1}\\\\ = tan^{-1} \ (-\sqrt{3})

                   \sf = \dfrac{-\pi }{3}

n = 4

For k = 0,

          \sf z = \sqrt[4]{10}\left[Cos \ \dfrac{\dfrac{-\pi}{3} +0}{4}+iSin  \ \dfrac{\dfrac{-\pi}{3}+0}{4}\right] \\\\\\z= \sqrt[4]{10} \left[Cos \ \dfrac{ -\pi  }{12}+iSin  \ \dfrac{-\pi}{12}\right]\\\\\\z = \sqrt[4]{10}\left[-Cos \ \dfrac{\pi}{12}-i \ Sin \ \dfrac{\pi}{12}\right]

For k =1,

         \sf z = \sqrt[4]{10}\left[Cos \ \dfrac{5\pi}{12}+i \ Sin \ \dfrac{5\pi}{12}\right]

For k =2,

       z = \sqrt[4]{10}\left[Cos \ \dfrac{11\pi}{12}+i \ Sin \ \dfrac{11\pi}{12}\right]

For k = 3,

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For k = 4,

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4 0
1 year ago
Can someone help me solve this?
julsineya [31]

Answer:

im sorry i cant see that

Step-by-step explanation:

8 0
3 years ago
Y>1 and y>x on a graph
zlopas [31]

So,

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1. Graph each inequality separately.

2. Choose a test point to determine which side of the line needs to be shaded.

3. The solution to the system will be the area where the shadings from each inequality overlap one another (purple area)

As for the system of inequalities we say it's unbounded.

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3 years ago
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