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zimovet [89]
3 years ago
10

The Pep Club sold $125 worth of candy at Friday's night game. if they receive a commission of 40% of their candy sales, how much

did they make?
Mathematics
2 answers:
cluponka [151]3 years ago
8 0

Answer:

$175

Step-by-step explanation:

If by commission you mean the money they add to the candy bars revenue then the formula for that would be 125 * 1.4 = x. x = 175.

madam [21]3 years ago
6 0

Answer:

50$

Step-by-step explanation:

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A student solved for the radius of a circle with a circumference of 12π
padilas [110]

Answer:

Step 4 is incorrect  he did not divide correctly from step3 to step 4

Step-by-step explanation:

The circumference of a circle is

C = 2 * pi *r

We know the circumference is 12 pi

12pi = 2 pi *r

Divide each side by 2 pi

12 pi/2pi = 2pi r/ 2pi

6 = r

From step 3 The student did not cancel the pi in the top and the bottom on the right hand side to isolate r

In step 4 he got 6 =pi r  instead of pi

3 0
3 years ago
If my dog was born 4 weeks before August 27th how old will my dog be
Elenna [48]

Answer:

the dog was born on july 30th so the dog would be 3 months and a week old

Step-by-step explanation:

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3 years ago
What is the constant proportionality in the equation 3 y=2x
Dima020 [189]

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2

Step-by-step explanation:

8 0
3 years ago
The vertices of ABC are A(-2, 2), B(6,2), and CO, 8). The perimeter of ABC?
Alexxx [7]

Answer:

Perimeter = 22.809836694575                              

Step-by-step explanation:

A(-2, 2)  ;  B(6,2)  ;  C(0, 8)

AB=\sqrt{\left( 6--2\right)^{2}  +\left(2-2 \right)^{2}  } =\sqrt{64} =8

AC=\sqrt{\left( 0--2\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{40} =2\sqrt{10}

BC=\sqrt{\left( 0-6\right)^{2}  +\left(8-2 \right)^{2}  } =\sqrt{72} =6\sqrt{2}

Then

The perimeter of ΔABC = AB + BC + AC

                                       =8+6\sqrt{2} +2\sqrt{10}

                                       = 22.809836694575

3 0
2 years ago
Which answer is closest to the true value of the expression:
d1i1m1o1n [39]
(9.1\times10^4)(1.1\times10^{-5})(log10^{-13})(1000)\\\\=(9.1\times1.1)(10^4\times10^{-5}\times10^3)(-13log10)\\\\=10.01\times10^{4-5+3}(-13)\\\\=-130.13\times10^2\\\\=-13013\approx-13000\\\\Answer:(c).

6 0
3 years ago
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