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lesya692 [45]
3 years ago
5

Which point is located at (8, 6)? A B C D​

Mathematics
2 answers:
Sav [38]3 years ago
6 0

Answer:

the point located at (8,6) is A

Step-by-step explanation:

since A is the point there whose coordinates are ( 8,6 )

forsale [732]3 years ago
4 0

Answer: (8, 6) is located at Area A.

Step-by-step explanation:

The first number inside the parentheses can be found on the x-axis. The second on the y-axis.

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A direct variation function contains the points (-9, -3) and (-12, -4). Which equation represents the function?
Lisa [10]

Answer:

y=\frac{1}{3} x

Step-by-step explanation:

we need a function that when we plug the value of x, we get the given value of y.

In the coordinate point

(-9, -3)

the x and y values are:

x = -9

y = -3

so we can see that the value of y is one third of the x value (because -9/3 = -3):

y=\frac{1}{3} x

this is also true for the secod point:

(-12, -4)

here the x and y values are:

x = -12

y = -4

again the y value is one third of the x value (because -12/3 = -4):  

y=\frac{1}{3} x ⇒ this is the equation that represents the function.

6 0
3 years ago
Let A = −2 2 1 −3 1 1 2 0 −1 and B = 2 −1 0 1 2 1 −1 −2 4 . Use the matrix-column representation of the product to write each co
BigorU [14]

Answer:

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

Each column of AB is written as a linear combination of columns of Matrix A in the explanation below.

Step-by-step explanation:

A = \left[\begin{array}{ccc}-2&2&1\\-3&1&1\\2&0&-1\end{array}\right]

B= \left[\begin{array}{ccc}2&-1&0\\1&2&1\\-1&-2&4\end{array}\right]

We need to write each column of AB as a linear combination of the columns of A so we will multiply each column of A with each column element of B to get the column of AB. So,

AB Column 1 = 2 * \left[\begin{array}{ccc}-2\\-3\\2\end{array}\right]  + 1 \left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-1) \left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}-3\\-6\\5\end{array}\right]

AB Column 2 = (-1)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + 2\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + (-2)\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}4\\3\\0\end{array}\right]

AB Column 3 = (0)\left[\begin{array}{ccc}-2\\-3\\2\end{array}\right] + (1)\left[\begin{array}{ccc}2\\1\\0\end{array}\right] + 4\left[\begin{array}{ccc}1\\1\\-1\end{array}\right] = \left[\begin{array}{ccc}6\\5\\-4\end{array}\right]

Finally, we can combine all three columns of AB to form the 3x3 matrix AB.

AB = \left[\begin{array}{ccc}-3&4&6\\-6&3&5\\5&0&-4\end{array}\right]

4 0
3 years ago
“Peaches at the Farmer’s Market cost $2.70 per pound.”
koban [17]

Answer:

non-proportional

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the x !<br> please hurry! Thank you!
wolverine [178]

Step-by-step explanation:

2x+98=180° (angles in straight line )

2x=180-98

x=2/2

x=1

6 0
2 years ago
Read 2 more answers
A function, f(x)=4x+5, has a domain 0&lt;=x&lt;=50. What is the range? How do you do this??
babunello [35]

Step-by-step explanation:

remember the domain is the interval or set of valid input (x) values. the range is the interval or set of the valid result (y) values.

so, the given domain tells us the interval to look at.

what are the functional values of the function between 0 and 50 ?

since the function is continuous (there are no gaps) in this interval, we can safely assume that all values between f(0) and f(50) are valid y values.

f(0) = 4×0 + 5 = 5

f(50) = 4×50 + 5 = 205

so, the range is 5 <= y <= 205

3 0
3 years ago
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