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3 years ago

Basic algebra. PLease help!!!

Mathematics

2 answers:

spayn [35]3 years ago

4 0

There’s no question?

ludmilkaskok [199]3 years ago

4 0

Answer:

I really hope I am right!

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What is the following product? (4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

7 0

3 years ago

Round your answer to the nearest hundredth.

Nat2105 [25]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The length of a rectangular floor is 2m longer than it's width w. the area of the floor is 120m^2

KengaRu [80]

the width is 60

hopes this helps you

6 0

3 years ago

Help I need it helppp

natulia [17]

Answer:

1. x= -11/3

2. x= 25

hope it helps this is solved by functions

3 0

3 years ago

Amy had 23 blocks she gave 7 blocks to isabela and 5 blocks to alexa here are the choices A. (23-7)+5 and B.23-(7+5) and C. 23-7

Semmy [17]

Answer:

C seems right

Step-by-step

seems more work then needs be but 7+5= 12 and she originally had 23. so the equation of adding the 7+5 would just be adding up the ones removed together then adding the -23 to the equation is how many Amy had to begin with. so it would be 23-7+5 = 12. others dont seem right since when you add () to an equation that means your multiplying and you wouldn't be multiplying here and for D to be right it needs to be switched around or you'd end up with a - number and she wouldn't have a - number of blocks. just divide up a problem if need be and break it down to smaller parts to make it easier to deal with.

6 0

3 years ago