Your answer is y = -(13/3)x + 11/3. I have put the brackets to show that the entire fraction is negative, they do not do anything else.
First we need to find the slope of the line using the equation (y2 - y1)/(x2 - x1), so we get (3/2 - 1/5)/(1/2 - 4/5). To make this easier, I did each subtraction separately:
3/2 - 1/5 = 15/10 - 2/10 = 13/10
1/2 - 4/5 = 5/10 - 8/10 = -(3/10)
And then we need to divide 13/10 by -(3/10), so:
13/10 ÷ -(3/10) = 13/10 × -(10/3) = -(130/30) = -(13/3), which is our slope.
Then, we can write the equation y = -(13/3)x + c, and substitute in coordinates:
3/2 = (-13/3 × 1/2) + c
3/2 = -(13/6) + c
c = 11/3
So the final equation is y = -(13/3)x + 11/3.
I hope this helps!
Answer:
Step-by-step explanation:
M=16/21
I subtracted 1/12m from 3/4m and divided from both sides to get the answer.
9514 1404 393
Answer:
- vertical shift: 7 (up)
- horizontal shift: 2 (right)
- vertical asymptote: x=2
- domain: x > 2
- range: all real numbers
Step-by-step explanation:
For any function f(x), the transformation f(x -h) +k represents a horizontal shift of h units to the right and k units upward.
Here, the parent function is log₂(x) and the transformation to log₂(x -2) +7 represents translation 2 units right and 7 units upward.
The parent function has a vertical asymptote at x=0, so the shifted function will have a vertical asymptote at x-2=0, or x = 2.
The parent function has a domain of x > 0, so the shifted function will have a domain of x-2 > 0, or x > 2.
The parent function has a range of "all real numbers." Shifting the function vertically does not change that range. The range of the shifted function is still "all real numbers."
The graph is shown below. The vertical asymptote is the dashed orange line.
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The "work" is in matching the pattern f(x -h) +k to the function log₂(x -2) +7.