Question

Can you help me with it please​

Answer 1

Answer:

$\frac{20}{29}$

Step-by-step explanation:

Equation of unit circle is:

$x^2 + y^2 = 1$

Plug $y = \frac{-21}{29}$ in above equation.

$x^2 + \bigg( \frac{-21}{29}\bigg)^2 = 1\\\\x^2 + \frac{441}{841} = 1\\\\x^2 = 1-\frac{441}{841}\\\\x^2 = \frac{841-441}{841}\\\\x^2 = \frac{400}{841}\\\\x =\pm\sqrt{ \frac{400}{841}}\\\\x =\pm\frac{20}{29}$

Since, point P is in the fourth quadrant.

Therefore, x - coordinate should be positive.

$\huge \red {\boxed {\therefore x =\frac{20}{29}}}$