Simplify the expression.
1 answer:
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Example case:
The second equation is twice the first, so subtracting that from the second equation yields the identity 0 = 0.
This is an identity. It's an equation that holds true (clearly, 0 is the same as 0) regardless of the values of the variables, which means any pair of numbers
is a solution to the system.
The second equation is twice the first, so subtracting that from the second equation yields the identity 0 = 0.
This is an identity. It's an equation that holds true (clearly, 0 is the same as 0) regardless of the values of the variables, which means any pair of numbers
Answer:
and
Step-by-step explanation:
The sequence is given by .
Now, putting n = 1, .
Now, putting n = 2,
Therefore, .........(1)
Again, putting n = 3,
Therefore, .......... (2)
Hence, from equations (1) and (2), we can write
and
So, this above relation gives the recursive rule for the given sequence. (Answer)
Answer: 1.75
Step-by-step explanation:
To find the value of
Now,
Since dy is approximately equals to then ,
Thus , the approximate value of