Solve for x. Show your work.

Mathematics

1 answer:

puteri [66]3 years ago

6 0

So, these are actually pretty simple once you learn the equality used to solve for "x" and when to implement this method. You can use this equality to solve for a segment "x" anytime that two secant lines cutting through a circle come from the same point outside the circle.

Secant: by geometric definition is just a straight line that cuts a curve into multiple pieces.

I did one of them for you hopefully you can use my work for "a" to help you solve for "b". For a. I got x=7.

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What are the restrictions for (x^2+10x+25)/(x^2-3x-28) 0,14 -4,7 0,7 4,7

nirvana33 [79]

The answer is -4,7

The denominator can't equal zero. Factor the denominator:
x^2 - 3x - 28=
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a_sh-v [17]

substitute 4 as x in both sides of the equation

basically multiply -3/2 by 4