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3 years ago

As pointed out, you lose if the pile has 1, 6, 11 or 16 sticks. How many sticks are needed in the next two piles for you to lose

Mathematics

1 answer:

muminat3 years ago

4 0

Answer:

21 and 26 totaling 47sticks

Step-by-step explanation:

Th number of sticks form an arithmetic progression

1, 6, 11, 16...

The nth term of an arithmetic progression is expressed as;

Tn = a+(n-1)d

a is the first term = 1

d is the common difference

d = 6-1 = 11-6 = 5

n is the number of terms

The next two terms are the fifth and sixth term

T5 = 1+(5-1)5

T5 = 1+4(5)

T5 = 1+20

T5 = 21

T6 = 1+(6-1)5

T6 = 1+5(5)

T6 = 1+25

T6 = 26

Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks

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elixir [45]

Answer:

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Step-by-step explanation:

We have been given that at a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m.

To find the area of the side walk we will subtract the area of inner edge of the side walk of lion pen from the area of the outer edge of the lion pen.

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$\text{Exact area of the sidewalk}=\pi*\text{(11 m)}^2-\pi*\text{(9 m)}^2$

$\text{Exact area of the sidewalk}=\pi*\text{121 m}^2-\pi*\text{81 m}^2$

$\text{Exact area of the sidewalk}=40 \pi\text{ m}^2$

Therefore, the exact area of the side walk is $40 \pi\text{ m}^2$

To find the approximate area of side walk let us substitute pi equals 3.14.

$\text{Approximate area of the sidewalk}=40*3.14\text{ m}^2$

$\text{Approximate area of the sidewalk}=125.6\text{ m}^2$

Therefore, the approximate area of the side walk is $125.6\text{ m}^2$ .

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Answer:

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Step-by-step explanation:

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