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Ulleksa [173]
3 years ago
15

Solve for X y and z brainliest

Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

Step-by-step explanation:

"y" is geometric mean

y² = 13 × 2

<em>y </em>= √26 <em>≈</em><em> 5.1</em>

x² = 26 + 4 = 30

<em>x</em> = √30 <em>≈</em><em> 5.5</em>

z² = 15² - 30 = 195

<em>z </em>= √195 <em>≈</em><em> 14.0</em>

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Kate and Jean paint a house together in 6 days. If they work alone, Kate takes 5 fewer days than Jean would take to do the same
ELEN [110]
Katework+jeanwork=6
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Katework=-5+Jeanwork
ad 5 to both sides
Katework+5=jeanwork
subsitute 5+katework for jeanwork
5+katework+kateworkwork=6
subtract 5 from both sides
2katework=1
divide both sides by 2
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equation would be
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3 years ago
Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______
Vesna [10]

Answer:

c = 11

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

a = b= 5

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

a + b > c

a + c > b

b + c > a

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: a = b= 5

5 + 5 > c ===> 10 > c

5 + c > 5  ===> c > 5 - 5 ===> c > 0

5 + c > 5  ===> c > 5 - 5 ===> c > 0

The results of the inequality is: 10 > c and c > 0

Rewrite as: c > 0 and c < 10

0 < c < 10

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

c = 11, since no options are given

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