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Lilit [14]
2 years ago
15

Find all the numbers for each shape

Mathematics
1 answer:
irina1246 [14]2 years ago
8 0

Answer:

  • 1 = pentagon
  • 2 = diamond
  • 3 = square
  • 5 = circle
  • 6 = rectangle
  • 7 = oval
  • 8 = triangle
  • 9 = hexagon
  • 10 = trapezoid

Step-by-step explanation:

Each half of a hanger divides the total weight in half. The right-most vertical has a total weight of 80/16 = 5. It consists of a square and a diamond, and we know the square is 1 more than the diamond. That means 2 diamonds weigh 5 -1 = 4. A diamond weighs 2, and a square weighs 3. The other half of that balance is a circle, which weighs 5.

The total of a square and oval is 10, so the oval is 10 -3 = 7. The two trapezoids weigh 20, so each is 10.

The second vertical from the left is a circle and diamond which will weigh 5+2 = 7. That makes the sum of a pentagon and rectangle also be 7. The 7+7 = 14 below the square on the left branch makes the total of that branch be 14+3 = 17, which is also the sum of the triangle and hexagon.

The weight below the rectangle at top left is 17+17 = 34, and the weight of that entire branch is 40. Thus the rectangle is 40-34 = 6, which makes the pentagon 7-6 = 1.

We require the sum of the triangle and hexagon be 17, with the triangle being the smaller value, and both being 9 or less (the trapezoid is the only figure weighing more than 9). Hence the triangle is 8 and the hexagon is 9.

The weights are summarized in the answer section, above.

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the measure of two complimentary angles is in the ratio 1:9. what are the degree measures of the two angles
marusya05 [52]
x+9x=90\\
10x=90\\
x=9\\
9x=9\cdot9=81

9 and 81.
4 0
3 years ago
Find the value of each variable using sine and cosine. Round your answers to the nearest tenth.
Alisiya [41]

Answer:

x ≈ 9.5 , y ≈ 15.3

Step-by-step explanation:

sin32° = \frac{opposite}{hypotenuse} = \frac{x}{18} ( multiply both sides by 18 )

18 × sin32° = x , then

x ≈ 9.5 ( to the nearest tenth )

cos32° = \frac{adjacent}{hypotenuse} = \frac{y}{18} ( multiply both sides by 18 )

18 × cos32° = y , then

y ≈ 15.3 ( to the nearest tenth )

5 0
2 years ago
Write an equation of a line that goes through the point (-9, 3), and is perpendicular to the line 3x + y = 5
Vlad [161]
To find the slope of the line, first find the slope of 3x + y = 5, and then its opposite reciprocal.

3x + y = 5
y = -3x + 5
the slope of 3x + y = 5 is -3.

the slope is -3, so the opposite reciprocal slope is 1/3.

the equation of any line is y = ax + b
to find this line, y = 3, x = -9, and the slope is 1/3.

3 = -9a + b
3 = -9 (1/3) + b
3 = -3 +b
b = 6

substitute a and b into the equation
y = ax + b
y = 1/3x + 6

the equation of the line is y = 1/3x + 6.


3 0
3 years ago
The value of a company's equipment is $25,000 and decreases at a rate of 15% per year. What is the value after 9 years?
Sindrei [870]

Answer:

6,812.26

Step-by-step explanation:

I found the answer key

7 0
3 years ago
Consider <img src="https://tex.z-dn.net/?f=%24%5Ctriangle%20ABC%24%20such%20that%20%24BC%20%3D%203AC%24%20and%20%24%5Cangle%20A%
Gemiola [76]

The answer to the question is,

12 sin(∠B) = 2,           12 sin(∠C) = √3+√35

Sin rule is,

sin(A)/BC = sin(B)/AC = sin(C)/AB

sin(B) = (sin(A)×AC)/BC

sin(C) =(sin(B)×AB)/AC

To solve this question we apply sin rule,

Now we take

12 sin(∠B) =12 (sin(∠A)×AC)/BC

12 sin(∠B) =12 (sin(π/6)×(x/3x))          where ∠A =π/6 and AC=x, BC =3x

12 sin(∠B) =12 ((1/2)×(1/3))

12 sin(∠B) =12/6 = 2

12 sin(∠B) = 2

now we find the value of 12 sin(∠C)

12 sin(∠C) = 12(sin B)×(AB/BC)

now put the value of 12 sin(∠B) = 2

12 sin(∠C) = 2×(AB/BC)

12 sin(∠C) = (2/AC)×[AC×(cos(π/6))+BC×(cos B)]

12 sin(∠C) = 2×[cos(π/6)+(BC/AC)×(cos B)]

cos (π/6) = √3/2 and BC/AC =3

then

12 sin(∠C) = 2×[(√3/2)+3×(cos B)]

cos B= √1-sin²B

12 sin(∠C) = 2×[(√3/2)+3×√(1-sin²B)]

12 sin(∠B) = 2

sin B = 1/6

12 sin(∠C) = 2×[(√3/2)+3×√(1-(1/6)²]

12 sin(∠C) = 2×[(√3/2)+3×√1-(1/36)]

12 sin(∠C) = 2×[(√3/2)+3×√(36-1)/36]

12 sin(∠C) = 2×[(√3/2)+3×√(35/36)]

12 sin(∠C) = 2×[(√3/2)+(3/6)×√35]

12 sin(∠C) = 2×[(√3/2)+(1/2)×√35]

12 sin(∠C) = 2×[(1/2)(√3+√35)]

12 sin(∠C) = √3+√35

Hence the answer is,

12 sin(∠B) = 2,         12 sin(∠C) = √3+√35

Learn more about triangles rules from:

brainly.com/question/27998693

#SPJ10

6 0
2 years ago
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