Answer:
No
Step-by-step explanation:
We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.
quadratic equation is given by ax^2+bx+c=0 It can be written as the product of linear factors ax^2+bx+c=a(x-r_1)(x-r_2) Where r_1,r_2 are solutions of the given polynomial equation.
Hope it helps! :]
3 small 3 larger good sir
Answer:
i think factoring
Step-by-step explanation:
J = 0 because it is the midpoint of K and P.
Since we know that K is at -5 and P is at 5, KP = 10
Both KP and JQ are equal to 10, therefore, they are equal.
Distribute the five to [3q-10]
Combine like terms [15q] and [-5q]
Add 50 on each side
Divide by 10 on each side
Simplify