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2 years ago

"People should not be afraid of their governments.

Mathematics

2 answers:

QveST [7]2 years ago

5 0

Yeshshahahahhahahahaha yes

zhuklara [117]2 years ago

4 0

Answer:

YESSSSSSSSSSSSSSSSSS

i mean theres a ton of us we can over power them anytime!

You might be interested in

Two apples and three peaches cost $1.65. three apples and two peaches cost $1.60. what is the cost of one peach

marta [7]

Apples = $.30
Peaches = $.60

You can get this by setting up a system of equations that looks like this.

2x + 3y = 1.65
3x + 2y = 1.60

Where x is the amount of apples and y is the number of peaches. Then you can solve using any of the methods (I would suggest elimination for ease).

7 0

2 years ago

Will give Brainliest to first person to give right answer!!!

faltersainse [42]

Answer:

35%

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Please help with this arc equation.

boyakko [2]

Answer:

Part 1) $arc\ AB=49^o$

Part 2) $arc\ ABC=204^o$

Part 3) $arc\ BAC=156^o$

Part 4) $arc\ ACB=311^o$

Step-by-step explanation:

Part 1) Find the measure of arc AB

we know that

$arc\ AB=m\angle AOB$ ----> by central angle

we have

$m\angle AOB=49^o$

therefore

$arc\ AB=49^o$

Part 2) Find the measure of arc ABC

we know that

The central angle of complete circle is equal to 360 degrees

$arc\ ABC=360^o-107^o-49^o=204^o$

Part 3) Find the measure of arc BAC

we know that

$arc\ BAC=arc\ BA+arc\ AC$ ----> by angle addition postulate

we have

$arc\ BA=49^o$ ---> by central angle

$arc\ AC=107^o$ ---> by central angle

$arc\ BAC=49^o+107^o=156^o$

Part 4) Find the measure of arc ACB

we know that

The central angle of complete circle is equal to 360 degrees

$arc\ ACB=360^o-arc\ AB$

substitute

$arc\ ACB=360^o-49^o=311^o$

4 0

2 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

1 year ago

A blank is a unit rate with a denominator of 1 unit. What is the the blank?

Bumek [7]

A unit rate is a ratio that has a denominator of 1. A unit rate is also called a unit ratio. (They mean the same thing.)

\frac{5}{4} and 3:8 and 40\mbox{ to }10 are ratios, but they are not unit ratios.

\frac{1.25}{1} and 0.375:1 and 4\mbox{ to }1 are unit ratios.

Any ratio can be converted into a unit ratio by dividing the numerator and the denominator by the denominator.

4 0

2 years ago