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ivann1987 [24]
3 years ago
15

Sara created the poster shown below What would be the dimensions of the poster at times its current size with:32 lenth:28

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0
D because it’s the best because you need a lot of room when using a poster
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How many different anagrams can you make for the word MATHEMATICS?
Alex73 [517]

Answer:

4989600

Step-by-step explanation:

The given word is MATHEMATICS

Number of letters in the given word is 11

there are 2 M's, 2 A's and 2 T's

the given word is arranged in 11! ways

three letters are repeating, so we divide by repeating occurrences

number of different arrangements =\frac{11!}{2!2!2!}

= 4989600

7 0
3 years ago
Solve 12x<br>x + 16 - 1 = 0<br>​
zhuklara [117]

Answer:

xx=-0.8

Step-by-step explanation:

not sure if this is right because the 12xx is kind of strange

12xx+16-1=0
12xx+15=0
12xx=-15
12/12xx=12/-15
xx=-.8

5 0
2 years ago
Evaluate each expression for g = -7 and h = 3 and match it to its value. 1. g + h 2 2. g - h 46 3. h - g -21 4. gh -4 5. g + h2
Ivanshal [37]

Answer:

1. -4

2. -10

3. 13

4. -21

5. 2

6. 46

Step-by-step explanation:

To evaluate the expression, substitute g= -7 and h = 3. Then simplify using order of operations.

1.  g-h = -7 + 3 = -4

2. g-h = -7 - 3 = -10

3. h-g = 3 - -7 = 3+10 = 13

4.gh = -7(3) = -21

5. g+h^2 = -7 + 3^2 = -7+9 = 2

6. g^2-h = (-7)^2 -3 = 49 -3 = 46

3 0
3 years ago
Read 2 more answers
What is 18 expressed as a percent?
Vladimir79 [104]
Here is your answer:

Your answer is 18%

Reason: That's because 18 has a invisible decimal point:

18.

Then you move to decimal and change it into a %

Which will make it 18%

Your answer is...
18%
3 0
3 years ago
Read 2 more answers
Find the largest possible area of a rectangle with base on x-axis and vertices on curve y = 4 - x^2
astraxan [27]
The region bounded by the parabola and the x-axis is symmetric, so any inscribed rectangle whose base lies in the x-axis will have its base extend symmetrically around the origin, i.e. if the base has length 2a, with a>0, then its base is the line segment connecting the points (-a,0) and (a,0).

The height of such a rectangle will then by 4-(\pm a)^2=4-a^2.

The area of such a rectangle is then a function of a:

A(a)=2a(4-a^2)=8a-2a^3

Differentiating with respect to a gives

A'(a)=8-6a^2

which has critical points at

8-6a^2=0\implies a=\pm\dfrac2{\sqrt3}

We omit the negative root. Checking the sign of the second derivative at the positive critical point (it's negative) confirms that a=\dfrac2{\sqrt3} is the site of a local maximum.

This means the largest area of this rectangle is

A\left(\dfrac2{\sqrt3}\right)=\dfrac{32}{3\sqrt3}
3 0
3 years ago
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