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2 years ago

The temp at noon was 3F and in midnight the temp dropped 8F. What was the temp at midnight?

Mathematics

1 answer:

Romashka [77]2 years ago

6 0

Answer: -5°F

Step-by-step explanation:

The temp at noon was 3*F and in midnight the temp dropped 8*F. Therefore, the temp at midnight will be calculated as:

= 3°F - 8°F.

= -5°F

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Need help with this ASAP

Mariana [72]

Answer:

Sequence: 13, 20, 27

Rule: Tn = 7n + 6

Step-by-step explanation:

The 3 other numbers that can form an arithmetic progression is 13, 20, 27...

The nth term of an arithmetic progression is expressed as;

Tn = a + (n-1)d

a is the first term = 13

n is the number of terms

d is the common difference = 20 - 13 = 27 - 20

d = 7

Substitute

Tn = 13 + (n-1)(7)

Tn = 13 + 7n - 7

Tn = 7n+13-7

Tn = 7n + 6

This gives the required rule

5 0

3 years ago

A shipping service restricts the dimensions of the boxes it will ship for a certain type of service. The restriction states that

Igoryamba

Answer:

w =< 70

(width is less or equal to 70 inches)

Step-by-step explanation:

Let l = length, w = width, h = height

Restrictions given in this question:

'sum of perimeter of the base and the height cannot exceed 130 inches'

perimeter of the base is 2 width and 2 length of the box

perimeter = 2w + 2l

Therefore, inequality involves here is

2w + 2l + h =< 130

(Note that =< here means less or equal)

Then a new condition given with

height, h = 60 in

and length is 2.5 times the width

l = 2.5w

Substitute this new condition into the equation will give us the following:

2w + 2(2.5w) + 60 =< 130

2w + 5w + 60 =< 130

7w + 60 =< 130

7w =< 130-60

7w =< 70

w =< 10

4 0

2 years ago

Help plz plz plz plz .

nikklg [1K]

The y intercept is where the line hits the verticals line of the graph. Hope this helps!

7 0

3 years ago

A certain television is advertised as a 85 inch TV if the width of the TV is 67 how tall is the TV

Lunna [17]

Answer:

I believe the answer is 12

4 0

2 years ago

Read 2 more answers

Given limit f(x) = 4 as x approaches 0. What is limit 1/4[f(x)]^4 as x approaches 0?

stepladder [879]

Answer:

$\displaystyle 64$

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Rule [Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to c} x^n = c^n$

Limit Property [Multiplied Constant]: $\displaystyle \lim_{x \to c} bf(x) = b \lim_{x \to c} f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \lim_{x \to 0} f(x) = 4$

Step 2: Solve

Rewrite [Limit Property - Multiplied Constant]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4} \lim_{x \to 0} [f(x)]^4$
Evaluate limit [Limit Rule - Variable Direct Substitution Exponential]: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = \frac{1}{4}(4^4)$
Simplify: $\displaystyle \lim_{x \to 0} \frac{1}{4}[f(x)]^4 = 64$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

3 0

2 years ago

The temp at noon was 3*F and in midnight the temp dropped 8*F. What was the temp at midnight?

The temp at noon was 3F and in midnight the temp dropped 8F. What was the temp at midnight?