Answer:
128
Step-by-step explanation:
N(t) = 4(2)^t
N(t) = 4(2)^5
N(t) = 4(32)
N(t) = 128
The answer is 3/2 because I multiply the 6 x 3/2 and get 9 and 8 x 3/2 and get 12
The first thing to do is to calculate how many ways you can choose 3 people from a set of eight. In order to do this, we need to use the attached formula.
(The letter 'n' stands for the entire set and 'r' stands for the number of objects we wish to choose.)
So we wish to choose 3 people ('r') form a set of 8 ('n')
combinations = n! / r! * (n - r)!
combinations = 8 ! / (3! * 5!)
combinations = 8 * 7 * 6 * 5! / (3!) * (5!)
combinations = 8 * 7 * 6 / 3 * 2
combinations = 56
Now of those 56 combinations, the 3 people can finish in 6 different ways.
For example, persons A, B and C could finish
ABC or ACB or BAC or BCA or CAB or CBA
So to get the TOTAL combinations we multiply 56 * 6 which equals
336 so the answer is (a)
A significant outcome is a meaningful result of an experiment as determined by statistical analysis. <span>Statistically significant results are those that are interpreted not likely to have occurred purely by chance and thereby have other underlying causes for their occurrence.</span>
