The temp at noon was 3F and in midnight the temp dropped 8F. What was the temp at midnight?

Mathematics

1 answer:

Romashka [77]3 years ago

6 0

Answer: -5°F

Step-by-step explanation:

The temp at noon was 3*F and in midnight the temp dropped 8*F. Therefore, the temp at midnight will be calculated as:

= 3°F - 8°F.

= -5°F

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A/ab-bsquare + b/ab-asquare?

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Answer:

$\dfrac{(a+b)}{ab}$

Step-by-step explanation:

The given expression is :

$\dfrac{a}{ab-b^2}+\dfrac{b}{ab-a^2}$

It can be solved as follows :

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So, the solution of the given expression is equal to $\dfrac{(a+b)}{ab}$ .

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First of all, a fifth degree polynomial means that the term with the highest degree is five.
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4 years ago

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In 1998 there were 1509 daily newspapers in the country. By 2003, there were only 1454 daily newspapers.

natta225 [31]

Answer:

The number of daily newspapers in 2000 is estimated in 1487

Step-by-step explanation:

Modeling Functions

Real-world situations are often modeled with mathematic functions. Functions allow making predictions and analysis to better understand and manage those situations

a. In our example, we know that in 1998 there were 1509 daily newspapers in the country. It gives us a starting point (0,1509), where the first coordinate is the years after 1998 and the second is the number of daily newspapers. The second point comes from the next data: by 2003 (5 years after 1998), there were 1454 daily newspapers. The new point is (5,1454).

b. Knowing the relationship between years after 1998 and the numbers of daily newspapers is linear, we can construct the function by using both points. The equation of a line, given the points (a,b) and (c,d) is

$\displaystyle y-b=\frac{d-b}{c-a}(x-a)$