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3 years ago

Need help with Geometry homework.

Mathematics

1 answer:

solmaris [256]3 years ago

7 0

Answer:

SU = 22

Step-by-step explanation:

SR = RU

4x - 1 = x + 8

3x - 1 = 8

3x = 9

x = 3

SR = 4(3) - 1 = 11

RU = 3 + 8 = 11

SU = 11 + 11 = 22

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2root3 sin^<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ac9eec">[email protected]</a> - <a href

Phantasy [73]

Answer:

Step-by-step explanation:

$2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3}) } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}$

$\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)$

$or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )$

5 0

3 years ago

PLEASE ANSWER I WILL GIVE YOU BRAINIEST!!!!!!!!!!!

Vedmedyk [2.9K]

Answer:

A. Both are correct

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What two number multiply to -48 and add to -2?

Novosadov [1.4K]

Answer:

6 and -8

Step-by-step explanation:

Solve:

xy = 48

x + y = -2

You can say y = -2-x = -(x+2) and then substitute that in the first:

-x(x+2) = 48

-x² -2x - 48 = 0

x² + 2x + 48 = 0

Quadratic formula can do the rest if you don't "see" the factorization.

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4 years ago

For what value(s) of k will the relation not be a function?

kolbaska11 [484]

Answer:

See below

Step-by-step explanation:

The relation is not a function when x -value is same but y- values are different.

k^2 = 4k
k = 0, k = 4

k^2 - 5k = k + 7
k^2 - 6k = 7
k^2 - 6k + 9 = 16
k - 3 = 4 ⇒ k = 7
k - 3 = -4 ⇒ k = -1

k^3 - 5k^2 + 3k = -k
k^3 - 5k^2 + 4k = 0
k(k^2 - 5k + 4) = 0
k = 0, k = 1, k = 4

|k + 1| + 2 = 8
|k + 1| = 6
k = 5, k = -7

8 0

3 years ago

You have 126 pieces of chocolate candy and 60 pieces of jolly ranchers to put into gift bags. You want identical groups of candy

madreJ [45]

Answer:

Six gift bags

Step-by-step explanation:

60/6 = 10 (limiting factor).

126/6 = 21

3 0

3 years ago