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Sergio [31]
3 years ago
9

Cot(-x)*sin(x) = -cos x

Mathematics
1 answer:
klio [65]3 years ago
5 0

Answer:

0

Step-by-step explanation:

first you will need to know the negative angle identities, which show that cot(-x)=-cot(x), you can then simplify that to -(cos/sin) so when you multiply by sin(x), or sin(x)/1, the sines cancel out and you are left with -(cos(x)/1)*(1/1) so your equation is now -cos(x)=-cos(x), so when you add the cosines over, you get zero

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Let f(x)=x2−2x−4 . What is the average rate of change for the quadratic function from x=−1 to x = 4?
goblinko [34]

Answer:

The average rate of change for f(x) from x=−1 to x = 4 is, 1

Step-by-step explanation:

Average rate A(x) of change for a function f(x) over [a, b] is given by:

A(x) = \frac{f(b)-f(a)}{b-a}

As per the statement:

f(x) = x^2-2x-4

we have to find the average rate of change from x = -1 to x = 4

At x = -1

f(-1) = (-1)^2-2(-1)-4 = 1+2-4 = -1

and

at x = 4

f(4) = (4)^2-2(4)-4 = 16-8-4 = 4

Substitute these in [1] we have;

A(x) = \frac{f(4)-f(-1)}{4-(-1)}

⇒A(x) = \frac{4-(-1)}{4+1}

⇒A(x) = \frac{5}{5}

Simplify:

A(x) = 1

Therefore, the average rate of change for f(x) from x=−1 to x = 4 is, 1

4 0
3 years ago
Read 2 more answers
Factor the expression. x2-x-6​
lisabon 2012 [21]

Answer:

(x+2)⋅(x−3)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Compute the difference​ quotient, StartFraction f (x plus h )minus f (x )Over h EndFraction f(x+h)−f(x) h​, for the function f (
lawyer [7]

Answer:

The difference quotient for f(x)=3x^2 is 3 h + 6 x.

Step-by-step explanation:

The difference quotient is a formula that computes the slope of the secant line through two points on the graph of <em>f</em>. These are the points with x-coordinates x and x + h. The difference quotient is used in the definition the derivative and it is given by

\frac{f(x+h)-f(x)}{h}

So, for the function f(x)=3x^2 the difference quotient is:

To find f(x+h), plug x+h instead of x

f\left(x+h\right)=3 \left(h + x\right)^{2}

Finally,

\frac{f\left(x+h\right)-f\left(x\right)}{h}=\frac{\left(3 \left(h + x\right)^{2}\right)-\left(3 x^{2}\right)}{h}

\frac{3\left(\left(h+x\right)^2-x^2\right)}{h} \\\\\frac{3(h^2+2hx+x^2-x^2)}{h} \\\\\frac{3h\left(h+2x\right)}{h}\\\\3h+6x

The difference quotient for f(x)=3x^2 is 3 h + 6 x.

4 0
3 years ago
18
asambeis [7]

Answer:

B

Step-by-step explanation:

When we have a horizontal translation on the x-axis, it means the translation in question would be affecting only the x component of our function

With respect to the question, what we have here is that we are going to take out some values from x (or add some values) to it

Thus;

f(x) = x^2 would be;

g(x) = (x-4)^2

Corresponding to a shift to the right of upto 4 units on the x axis

7 0
3 years ago
A block of wood measures 9.5 inches by 1.5 inches by 8 inches. What is the volume of the block of wood?
MatroZZZ [7]
114 is the answer hope this helps good luck and god bless!
6 0
3 years ago
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