The measure of one of the acute angles in a right triangle is given. What is the measure of the other acute angle?

Which of the following is the correct set of ordered pairs for The Jeans Source?

Anni [7]

Number 3 bc it’s by 25

5 0

3 years ago

In January, a dealership sold 164 vehicles. In February, the same dealership sold 23.8% fewer vehicles than they sold in January

sattari [20]

23.8% of 164 is 39.032 so minus that off of 164 and you would've sold 124.968 cars and im guessing you should round so the dealership would've sold 125 cars.

7 0

3 years ago

The size of a television is given by the length ofthe diagonal of the screen. the ratio of the height to the width of wide flat-

lbvjy [14]

The diagonal of the tv screen is given by:
d = root ((w) ^ 2 + (h) ^ 2)
Where,
w: width
h: height
In addition we have the following relationship:
h / w = 8/15
Thus,
For the width:
d = root ((w) ^ 2 + ((8/15) w) ^ 2)
For the high:
d = root (((15/8) h) ^ 2 + (h) ^ 2)
Answer:
The expressions for the width and height of a wide-screen tv in terms of the length of its diagonal are:
d = root ((w) ^ 2 + ((8/15) w) ^ 2)
d = root (((15/8) h) ^ 2 + (h) ^ 2)

5 0

3 years ago

Can someone please help with my math homework? this is so confusing.

nexus9112 [7]

Hi there friend, your answer for perimeter is 18.

I’ve included a graph below to help explain why but basically if you count the squares, each side measures 4 1/2 units so if you multiply 4 1/2 units by 4(the number of sides) you get 18.

4 0

3 years ago

SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

so

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

so

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

so

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago