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Trava [24]
3 years ago
7

Ill give brainlist to first answerrrrrrrrrrrrrrrr

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

18

The areas of a rectangle is lxw. You simply multiply by 3 x 6 and get this answer.

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What is 2-10+8-(-2)?
Alex

Answer:

your answer to your question is plain 2

6 0
3 years ago
There were 125 females and 100 males present at the high school pep rally. Find the ratio of males to the total number of people
riadik2000 [5.3K]
Total number of people = 125 + 100 = 225

Number of males = 100

Set as ratio

100:225

Simplify to 4:9 (can not simplify further without having decimals but you can’t have half a person)
5 0
3 years ago
(15/8+2/5)+(-7/8) show ur work
stepan [7]
The answer is 7/5 th. You can add fractions without first having a common denominator so you would change the 8's by multiplying it by 5 to get 40 and you would multiply the 5 by 8 to get 40 as well. And the rule whatever you do to the bottom you have to do to the top so whatever you multiplied 8 by do the same for the numerator and whatever you multiplied 5 by you do the same for the numerator. So your new equation would be (75/40+16/40)+(-35/40). you would then add the numerator's across to get 56 and the denominator would stay the same so the answer is 56/40. But you have to now simplify 56/40 down to 14/10 and then once more to 7/5 which is the final answer.
6 0
4 years ago
What is the value of this expression?
Darina [25.2K]
I think the answer is -32
7 0
4 years ago
The total service time of a multistep manufacturing operation has a gamma distribution with mean 18 minutes and standard deviati
11Alexandr11 [23.1K]

Answer:

The answer is "\bold{r=9,  \lambda=\frac{1}{2}\ and \ \  \text{exponential, 9 steps}}"

Step-by-step explanation:

In point a:

We are aware of the random gamma variable X:

\to \mathbb{E} =\frac{r}{\lambda}\\\\\to Std(X) =\frac{\sqrt{r}}{\lambda}\\\\

It is given:

\to \mathbb{E} = 18 \\\\\to std(X)=6

\to 18=\frac{r}{\lambda}\\\\ \to 6=\frac{\sqrt{r}}{\lambda}\\\\

Substituting the value:

\to \frac{\sqrt{r}}{6}=\frac{r}{18}\\\\\to r=9\\\\\to \lambda=\frac{1}{2}\\\\

In point b:

When building the Erlang/Gammas distribution, these could reasonably be assumed to become an exponential distribution only with \lambda = 1/2 parameter with one step but to be r = 9 for one step.

8 0
3 years ago
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