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Margarita [4]
3 years ago
14

What is the image of (-6,-1) after a reflection over the x axis

Mathematics
2 answers:
Levart [38]3 years ago
8 0

Answer:

(-6,1)

Step-by-step explanation:

The rule for reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same.

AVprozaik [17]3 years ago
3 0
(-6,1) Remember that the x-axis is the horizontal axis on a coordinate plane and the y-axis is the vertical axis in a coordinate plane. :)
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Question is attached​
Harrizon [31]

Hello!

\large\boxed{f^{-1} = \frac{5x+2}{4x-2}, f^{-1}(3) = \frac{17}{10} }

f(x) = \frac{2x +2}{4x - 5}

Find the inverse by swapping the x and y variables:

y = \frac{2x +2}{4x - 5}\\\\x = \frac{2y +2}{4y - 5}

Begin simplifying. Multiply both sides by 4y - 5:

x(4y - 5) = 2y + 2

Start isolating for y by subtracting 2 from both sides:

x(4y - 5) -2 = 2y

Distribute x:

4yx - 5x - 2 = 2y

Move the term involving y (4yx) over to the other side:

- 5x - 2 = 2y - 4yx\\\\

Factor out y and divide:

- 5x - 2 = y(2 - 4x)\\\\y = \frac{-5x-2}{-4x+2} \\\\y = \frac{-(5x + 2)}{-(4x - 2)} \\\\y^{-1} = \frac{5x + 2}{4x - 2}

Use this equation to evaluate f^{-1}(3)

f^{-1}(3) = \frac{5(3) + 2}{4(3) - 2}  = \frac{17}{10}

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Step-by-step explanation:

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I hope my answer has come to your help. God bless you and have a nice day ahead!
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