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3 years ago

Describe the transformation that maps the pre image A to the image A'

Mathematics

2 answers:

Leya [2.2K]3 years ago

4 0

Answer:

B) translated 6 units to the right then translated 9 units up

Step-by-step explanation:

Just use the graph to follow each translation until you get thee right answer, or you can count how many spaces are from the pre-image to the image. Just make sure to always use the same point.

Ivanshal [37]3 years ago

3 0

Answer:

B) translated 6 units to the right then translated 9 units up

Step-by-step explanation:

Did it on UsaTestPrep

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23) A ball is launched into the air. The function h=-16 +126 gives the height of the

Paul [167]

The equation is missing 't' terms. The correct equation is:

$h=-16t^2+126t$

Answer:

(a) 248.06 ft

(b) 7.875 s

Step-by-step explanation:

Given:

Height of ball in air above ground is given as:

$h=-16t^2+126t$

(a)

At maximum height, the speed of the ball is 0 momentarily. Speed is nothing but rate of change of height which is the first derivative of height with time. Therefore,

At maximum height:

Speed = 0

$h'=0\\-16(2t)+126=0\\-32t+126=0\\32t=126\\t=\frac{126}{32}=3.9375\ s$

Now, maximum height is obtained by plugging in $t=3.9375$ . Thus,

$h_{max}=-16(3.9375)^2+126(3.9375)\\h_{max}=-248.0625+496.125=248.0625\ ft$

Therefore, the maximum height of the ball is 248.06 ft. (Rounded to nearest hundredth)

(b)

Now, total time of travel of the ball is the sum of time taken to reach maximum height and the time taken from maximum height to the bottom.

Also, time taken for upward journey would be same as that of downward journey. Therefore, total time taken is twice that of the upward journey.

We have,

Time to reach maximum height, $t = 3.9375\ s$

Therefore, total time the ball was in air = $2(t)=2\times 3.9375=7.875\ s$

Hence, the ball was in the air for 7.88 s. (Rounded to nearest hundredth)

3 0

3 years ago

What is the length of a diagonal of a cube with a side length of 8 inches?

sashaice [31]

Answer:

13.9 inches

Step-by-step explanation:

Let the length of diagonal of cube be d inches.

$\therefore \: d = length \: of \: side \sqrt{3} \\ \hspace{16 pt} = 8 \sqrt{3} \\ \hspace{16 pt} =8 \times 1.73205081 \\ \hspace{16 pt} = 13.8564065 \\ \huge \red{ \boxed{\therefore \: d = 13.9 \: inches }}\\$