The base of a logarithm should always be positive and can't be equal to 1, so the domain is 0 < <em>x</em> < 1 or <em>x</em> > 1.

Write both sides as powers of 1/<em>x</em> :

Recall that
, so that



Take the 5th root of both sides, recalling that 3⁵ = 243, so
![x=\sqrt[5]{\dfrac1{243}}=\boxed{\dfrac13}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B5%5D%7B%5Cdfrac1%7B243%7D%7D%3D%5Cboxed%7B%5Cdfrac13%7D)
It would be a conjunction
Answer:
405
Step-by-step explanation:
Answer:
See explanation. (Also you can write an equation several different ways so without the choices I cannot tell you which)
Step-by-step explanation:
Slope-intercept form is y=mx+b
So one way to write the equation is y=-3/4 x +3/2
There are more ways to write it.
Every line about to write is a way to write it.
Multiply both sides by 4: 4y=-3x+6
Add 3x on both sides: 3x+4y=6
Subtract 6 on both sides: 3x+4y-6=0
There are a lot of ways to write an equation like this.
To better assist you I would need to see options.
Answer:
Step-by-step explanation:
(a - b)(a +b) = a² - b²
1 - Sin² A = Cos² A

2) Sec² A - Tan² A = 1

3) LHS = Cosec² A + Cot² A
= Cosec² A + Cosec² A - 1
= 2Cosec² A - 1 = RHS
