Simply multiply 4 for the terms in the parenthesis
4x-4
(1 yard )3<span> = 1</span>3<span> yard*yard*yard</span><span> = 1 yard*yard*yard</span><span> = 1 cubic yard . Since 1 yard = </span>3 feet, we have.
1 cubic yard = (1 yard)3<span> = (</span>3 feet)3<span> = </span><span>33 feet*feet*feet</span><span> = </span>27 cubic feet<span>.</span>
Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
