In order to calculate the volume of a cylinder, we can use the following formula:

Where r is the base radius and h is the height.
If the circumference is 8, we have:

Now, calculating the volume, we have:

So the correct option is the second one.
Let's make,
mechanic #1's rate = x
mechanic #2's rate = y
* Their rate is dollars per hour ($/hr)
mechanic #1 worked for 20 hours (hr × $/hr = $)
20x = money earned by mech#1
and mechanic #2 worked for 5 hours
5y = money earned by mech#2
together they charged a total of $1150. So the amount of money earned by both mechanics.
20x + 5y = 1150
the sum of the two rates was $95 per hour.
x + y = 95
which means
x = 95 - y
plug (95 - y) in for "x" in the other equation to get everything in terms of one variable.
20(95 - y) + 5y = 1150
solve for y
1900 - 20y + 5y = 1150
1900 - 15y = 1150
-15y = 1150 - 1900
-15y = -750
y = -750/-15
y = 50 $/hr
Now use this to solve for x
x + y = 95
x + 50 = 95
x = 95 - 50
x = 45 $/hr
mech#1 charged 45$/hr
mech #2 charged 50$/hr
Answer:
The probability is 
Step-by-step explanation:
From the question we are told that
The probability of the television passing the test is p = 0.95
The sample size is n = 10
Generally the comprehensive testing process for all essential functions follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as

=> ![P(X \le 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}]+ [^{10}C_{10} * {0.95}^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%7B0.95%7D%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \le 9) = [10 * 0.6302 * 0.05 ]+ [1 *0.5987 * 1 ]](https://tex.z-dn.net/?f=P%28X%20%5Cle%209%29%20%3D%20%5B10%20%2A%20%200.6302%20%20%2A%200.05%20%5D%2B%20%5B1%20%2A0.5987%20%2A%201%20%5D%20)
=> 