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densk [106]
3 years ago
8

Of the 150 students in 6th grade, 10% earned straight As last quarter. How many students earned straight As?

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

Answer: 15 students

Step-by-step explanation:

From the question, we are informed that there are 150 students in 6th grade, and that 10% earned straight As last quarter.

The number of students that earned straight As will be:

= 10% × 150

= 10/100 × 150

= 0.1 × 150

= 15 students

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I need help I can’t cuaet understand this
Gwar [14]

Answer:

B, 140

Step-by-step explanation:

Alright so if you know to do volume this should be a breeze!

First off what you want to do is find the volume of the outside prism.

V=whl=4·5·8=160

160

Then find the smaller prisms volume.

V=whl=1·5·4=20

20

Minus the smaller from the bigger

160-20=140

The answers B!

7 0
3 years ago
There are 196 countries in the world. How many students must be enrolled in a university to guarantee that there are at least 20
cestrela7 [59]

Answer:

At least 39200 students.

Step-by-step explanation:

Given that there are 196 countries in the world, and each country would have at least 200 students in a university.

For each country to have at least 200 students in the university, then;

Number of students enrolled in the university = number of required students x number of countries

                                      = 200 x 196

                                      = 39200

At least, 39200 students must be enrolled in the university. Provided that the admission procedures are conditioned for the purpose.

3 0
2 years ago
Yall im thinking A or B but can someone help?​
stiv31 [10]
It’s B, you go down 3 times from p and went over to the left 4 times and 3+4 =7
8 0
2 years ago
If EG=71 , find the value of x <br>​
Natalka [10]

Answer:

A

Step-by-step explanation:

A = 71 so then EG = 91

6 0
3 years ago
Please please please help me :(((​
Maslowich

Answer:

In the last diagram the object is being acted upon by forces not adding up to zero.

Step-by-step explanation:

(Assuming force 1=force 2 in terms of magnitude)

Let forces acting towards the left = -1

Let forces acting toward the right = +1

In the first diagram, force1 is acting towards the left and force2 is acting towards the right:

Total force = force1+force2=-1+1=0

In the second diagram, force1 is acting towards the left and force2 is acting towards the right:

Total force = force1+force2=-1+1=0

In the third diagram, force1 is acting towards the right and force2 is acting towards the left:

Total force = force1+force2=+1-1=0

In the fourth diagram, force1 is acting towards the left and force2 is acting towards the left:

Total force = force1+force2=-1-1=-2. Here, the forces do not add up to zero.

3 0
2 years ago
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