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lesya [120]
3 years ago
15

The sum of three prime numbers (other than two) is always odd.

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Step-by-step explanation:

The statement in the above question is True.

Sum of three prime numbers (other than  two)  is always odd.

Going by Christian Goldbach number theory ,

  • Goldbach stated that every odd whole number greater than 5 can be written as sum of three prime numbers .  

 Lets take an example,

  • 3 + 3 + 5 = 11
  • 3 + 5 + 5 = 13
  • 5 + 5 + 7 = 17

Later on in 2013  the Mathematician <u>Harald Helfgott</u> proved this theory true for all odd numbers greater than five.

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The attached image is the graph.

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Hi children pls find the area of this shape answer will get brainliest
Radda [10]

Answer.

Answer is 9

Step-by-step explanation:

Multiply height by with.

1,1x8,1

then do whatever that equals times 2,5 and you should get your answer.

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3 years ago
What is the a-value of the function, then determine if the graph opening up or down f(x)=−5(x+7)2+6?
Kay [80]
We know that
the equation of the vertical parabola in the vertex form is
<span>y=a(x-h)²+k
</span>where 
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then the parabola open downwards

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f(x)=−5(x+7)²<span>+6
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6 0
3 years ago
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Find the measure of an interior angle of a regular polygon with 6 sides. Round to the nearest tenth if necessary.
Andreyy89

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120

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2 years ago
100 Brainliest up for grabs to person who can answer all of these with no links:
kogti [31]

Using a discrete probability distribution, it is found that:

a) There is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

b) There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

c) The expected value is of 1.3 lawns mowed on a randomly selected day.

<h3>What is the discrete probability distribution?</h3>

Researching the problem on the internet, it is found that the distribution for the number of lawns mowed on a randomly selected dayis given by:

  • P(X = 0) = 0.2.
  • P(X = 1) = 0.4.
  • P(X = 2) = 0.3.
  • P(X = 3) = 0.1.

Item a:

P(X = 2) = 0.3, hence, there is a 0.3 = 30% probability that he will mow exactly 2 lawns on a randomly selected day.

Item b:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2 = 0.8

There is a 0.8 = 80% probability that he will mow at least 1 lawn on a randomly selected day.

Item c:

The expected value of a discrete distribution is given by the <u>sum of each value multiplied by it's respective probability</u>, hence:

E(X) = 0(0.2) + 1(0.4) + 2(0.3) + 3(0.1) = 1.3.

The expected value is of 1.3 lawns mowed on a randomly selected day.

More can be learned about discrete probability distributions at brainly.com/question/24855677

6 0
2 years ago
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