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Art [367]
3 years ago
11

Solve the following equation for

Mathematics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

b = h*D +hg^3

Step-by-step explanation:

b/h = D +g^3

Multiply each side by h

h* b/h = h*D +hg^3

b = h*D +hg^3

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Steve buys 2 lb of grapefruit and 3 lb of oranges for $7.20. Kennedy buys 4 lb of grapefruit and 2 lb of oranges for $8.80. Let
MrMuchimi

Answer: \left \{ {{2x+3y=7.20} \atop {4x+2y=8.80}} \right.

Step-by-step explanation:

Let be "x"  the price per pound for grapefruit, "y" the price per pound for oranges.

We know that Steve buys 2 pounds of grapefruit and 3  of oranges for $7.20.

This means that the sum of the products of 2x and 3y is $7.20. Then, we can write this equation to represent it:

2x+3y=7.20

Kennedy buys 4 pounds of grapefruit and 2 pounds of oranges for $8.80.

This means that the sum of the products of 4x and 2y is $8.80. Then, we can write this equation to represent this:

4x+2y=8.80

Therefore, we get that the system of equations that models the situation is:

\left \{ {{2x+3y=7.20} \atop {4x+2y=8.80}} \right.

8 0
3 years ago
Solve for h <br><br> 12h = 4(2h-5)<br><br> h=
Angelina_Jolie [31]
......,.... the answer is h= -5
3 0
3 years ago
Read 2 more answers
A pan has an original price of $32 but is marked down by 15%. which equation shows the new price of the pan
n200080 [17]
Don't really need an equation for this 
0.15 is 15% 
first 0.15 x 32 / 100 = 4.8

32 - 4.8  = 27.2  is the new price of the pan 
7 0
3 years ago
Read 2 more answers
What does |x| mean. I'm talking about the lines specifically.
Ymorist [56]
Those lines stand for the absolute value, or how far away it is from zero.

If you draw a number line from -3 to 3, and plot the points x = 2 and x = -2, what similarities do you see?
Although one is two units to the right of 0 and one is two units to the left of 0, both x = 2 and x = -2 are two units away from zero. Therefore, the absolute value of both 2 and -2 is 2.
3 0
3 years ago
Read 2 more answers
I need this to be simplified
umka2103 [35]

Answer:

\frac{x+2}{3x-1}

Explanation:

→ \frac{(x^2-9)(x+2)}{(3x^2 +8x -3)(x-3)}

→ \frac{\left(x+3\right)\left(x-3\right)\left(x+2\right)}{\left(3x^2+8x-3\right)\left(x-3\right)}

→ \frac{\left(x+3\right)\left(x+2\right)}{3x^2+8x-3}

→ \frac{\left(x+3\right)\left(x+2\right)}{\left(3x-1\right)\left(x+3\right)}

→ \frac{x+2}{3x-1}

8 0
2 years ago
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