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stellarik [79]
3 years ago
8

Multiply 6/5 by the reciprocal of (-3/8)

Mathematics
2 answers:
Damm [24]3 years ago
8 0

Answer:

Step-by-step explanation:

hello :

6/5 by the reciprocal of (-3/8)  means : ( 6/5 )(-8/3) = - 48/15 = -16/5

weeeeeb [17]3 years ago
4 0

Answer:

-48/15, simplified to -16/5

Step-by-step explanation:

The reciprocal of -3/8 is -8/3. So the equation will be 6/5 x -8/3. Multiply numerators then multiply denominators to get -48/15. This can simplify to -16/5 by dividing both by 3.

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Step-by-step explanation:

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A tower made of wooden blocks measures​114 feet high. Then a block is added that increases the height of the tower by 8 inches.
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It may be 114ft’ 8” or 1376 or 114.7
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2 years ago
The diameter of a tire is 2.5 ft. Use this measurement to answer parts a and b. Show all work to receive full credit.
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3 years ago
Help with math please example 1
hram777 [196]

Answer:

I'm not very sure about this one what icing in probably not going to be right but what I think is that they're not the same because look at the size difference imagine putting an adult's next to a baby that's kind of what it's like the bigger quadrilateral is also the adults while the little one is the baby what do you think about that I probably think that they're not saying

Step-by-step explanation:

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3 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
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