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tigry1 [53]
3 years ago
10

Find the value of x. 6 8 4 x

Mathematics
1 answer:
snow_tiger [21]3 years ago
8 0
Answer:

3

Explanation:

4 is half of 8 on the right side, so that means X has to be half of 6, so it’s 3. Also, it couldn’t be 2 because it is too big, and it can’t be 4 because it isn’t the same length as the other 4, so it’s 3
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the daily low temperatures in Kate's home town last week were 2°C,-9°C,-18°C,-6°C, you 3°C,0°C,and-7°C. Order the temperatures f
Artyom0805 [142]

Answer:

It would be 3C, 2C, 0C, -6C, -7C, -9C, then -18C

Step-by-step explanation:

This is because the larger a postive number is above 0, the greater it is. Along with this, the smaller a negative number is, the less it is.

8 0
3 years ago
Read 2 more answers
HELPPP ASAPPP I HAVE A PICTURE ABOVE
goblinko [34]

Answer:

b and d

Step-by-step explanation:

3 + root 2 = 4.414...

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5 0
2 years ago
Can someone answer the question ??
Temka [501]
Answer:
Faris' arrival time = 3:30 pm + 3 h 54 mnt = 7:24 pm
Step-by-step explanation:
Driving distance between Manchester to London = 195 miles
Coach left Manchester = 3.30 pm
Average speed of coach = 50 mph
Total time taken by the coach to reach the Manchester to London = 195÷50 = 3.9 h
0.9 h = 0.9×60 mnt = 54 mnt
Now,
3.9 h = 3 h 54 mnt
Hence Faris' arrival time in London = 3.30 pm + 3 h 54 mnt = 7.24 pm
5 0
3 years ago
30 POINTS
OverLord2011 [107]

Answer:

After 4 seconds the the ball will hit the ground

that is the correct answer

6 0
3 years ago
Prove: The product of the slopes of lines AC and BC is -1.
kicyunya [14]

Given that the AC and BC are perpendicular, their slopes are the negative inverse of each other which gives that the product of the slopes of AC and BC is -1

<h3>How can the prove that the product of the slopes is -1 be found?</h3>

The completed proof is presented as follows;

The slope of AC or GC is GF/FC by definition of slope. The slope of BC or CE is DE/CD by definition of slope.

<FCD = <FCG + <GCE + <ECD <u>by angle addition property </u> <FCD = 180° by the definition of a straight angle, and <GCE = 90° by definition of perpendicular lines. So by substitution property of equality 180° = <FCG + 90° + <ECD. Therefore 90° - <FCG = <ECD, by the <u>subtraction property of equality </u> . We also know that 180° = <FCG + 90° + <CGF by the triangle sum theorem and by the subtraction property of equality 90° - <FCG = <CGF, therefore <ECD = <CGF by the substitution property of equality. Then <ECD ≈ <CGF by the definition of congruent angles. <GFC ≈ <CDE because all right angles are congruent. So by AA ∆GFC ~ ∆CDE. Since <u>the ratio of corresponding sides of similar triangles are equal</u> then GF/CD = FC/DE or GF•DE = CD•FC by cross product. Finally, by the division property of equality GF/FC = CD/DE. We can multiply both sides using the slope of using the <u>multiplication property of equality </u> to get GF/FC × -DE/CD = CD/DE × -DE/CD. Simplify so that GF/FC × -DE/CD = -1. This shows that the product of the slopes of AC and BC is -1.

Learn more about perpendicular lines here:

brainly.com/question/20475360

#SPJ1

6 0
2 years ago
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