Step-by-step explanation:
cot x + 2 tan x + tan³ x
Write in terms of sine and cosine:
(cos x / sin x) + 2 (sin x / cos x) + (sin³ x / cos³ x)
Find the common denominator:
(cos⁴ x / (sin x cos³ x) + 2 (sin² x cos² x / (sin x cos³ x)) + (sin⁴ x / (sin x cos³ x))
Add:
(cos⁴ x + 2 sin² x cos² x + sin⁴ x) / (sin x cos³ x)
Factor:
(sin² x + cos² x)² / (sin x cos³ x)
Pythagorean identity:
1 / (sin x cos³ x)
Multiply top and bottom by cos x:
cos x / (sin x cos⁴ x)
Simplify:
cot x sec⁴ x
I think... J because
x + 1 / x^3 - x
Factor out x from the expression
x + 1 / xx(x^2 - 1)
Use a^2 - b^2 = (a - b)(a + b) to factor the expression
x + 1 / x • (x - 1) • (x + 1)
Reduce the fraction with x+ 1
1 / x • (x - 1)
Distribute x through the parentheses
1 / x^2 - x
:)
1. The lowest test score is 79.
The highest test score is 100.
The range is 21.
2. The median is 93.
3. The median of lower half is 89.
4. The median of upper half is 96.
Hope this helped! :)
Actually, this answer would be true. Why?
The first equation is: a(sub <em>n</em>) = 8, 13, 18, 23
The second is: a(sub 1)=8 ; a(sub <em>n</em>)= a(sub <em>n</em>-1)+5
if you wish to find the second term, plug two into the equation for <em /><em>n</em>
8+5=13
to find the third, plug the second term, 13, in for <em>n.</em>
13+5=18.
Hope this helped! I know it's a bit on the late side, but at least you can get the general idea!
