The set when z = -5 is {-27, -9, -5}
<h3>How to determine the set elements?</h3>
The set is given as:
{(4z-7,z-4,z) |z is any real number}
When z=-5, we have:
4z - 7 = 4(-5) - 7 = -27
z - 4 = -5 - 4 = -9
z = -5
So, we have:
{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}
Hence, the set when z = -5 is {-27, -9, -5}
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Answer:
No.
Step-by-step explanation:
To be a function, each input (x value) must go to exactly one output (y value). In this instance, the input 5 has an output of -15 and 4. This breaks the rule. Therefore, this relation is not a function.
Answer:
4(4g+5h)
Step-by-step explanation:
Factor out the 4.
Answer:
i think the answer is B hope i was helpful
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The sum to infinity of a geometric series is
( - 1 < r < 1 ) ← substitute values
S( ∞ ) = 
= 
= 
