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2 years ago

EHIE HELP PLS thank you so much you helped a lot , this is last problem

Mathematics

1 answer:

Mkey [24]2 years ago

8 0

Step-by-step explanation:

I think it's 8 down again.

And 7 down.

8•7 = 56

• = Multiplication

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Solve for x: 5x/7 - 5 = 50

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3 years ago

Lucia finds that (3x^2+3x+5)

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Step-by-step explanation:

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3 years ago

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Evaluate the expression [(3^-5)(3^4)]^3

Oksi-84 [34.3K]

Answer:

1/27

Step-by-step explanation:

[(3^-5)(3^4)]^3

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3 years ago

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Molodets [167]

Answer:

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Step-by-step explanation:

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2 years ago

Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)

Xelga [282]

Answer:

$\frac{x^2}{16}-\frac{b^2}{4}=1$

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4$

The foci c is at +/-2√5, using c² = a² + b²:

$c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2$

Substituting the value of a and b to get the equation of the hyperbola:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1$

5 0

3 years ago