Hello :
<span>(27ax^3 – 9a^2x) ÷ 3ax :
</span> <span>(27ax^3 – 9a^2x) / 3ax
</span> (27ax^3 ) / (3ax) –( 9a^2x) / 3ax = 9x² - 3a
Angle B = 60°
The complement of angle B is 90 - x.
60° + (90 - x)° = 180°
Can you take it from here?
Answer:
7
Step-by-step explanation:
Simply subtract 6 from 13.
13-6=7
Hope this helps! :)
1) Δ ABC
m∠B + m∠C + m∠BAC = 180⁰
2) m∠DAB + m∠BAC = 180⁰ because m∠DAB and m∠BAC are supplementary angles.
3) m∠B + m∠C + m∠BAC = m∠DAB + m∠BAC
m∠B + m∠C = m∠DAB
32⁰ + x = 98⁰
x=98 - 32 = 66 ⁰
Answer: A. 66⁰.
